Re: Question about sched_yield()

Stevie O (stevie@qrpff.net)
Tue, 18 Jun 2002 18:45:55 -0400

At 11:00 AM 6/18/2002 -0700, David Schwartz wrote:
>This is the same error repeated again. Since you realize that an endless
>loop on sched_yield is *not* equivalent to blocking, why do you then say "in
>fact doing useful work"? By what form of ESP is the kernel supposed to
>determine that the sched_yield task is not 'doing useful work' and the other
>task is?

By this form of ESP: sched_yield() means "I have nothing better to do right now, give my time to someone who does". If a thread is doing useful work, why would it call sched_yield() ?!?

--
Stevie-O


Real programmers use COPY CON PROGRAM.EXE


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