[patch] task_prio() fix

Robert Love (rml@tech9.net)
20 Feb 2003 18:42:40 -0500


Looks like task_prio() should do:

int task_prio(task_t *p)
{
return p->prio - MAX_RT_PRIO;
}

Instead of subtracting MAX_USER_RT_PRIO, since the maximum _user_ value
has nothing to do with the maximum that may be stored. The effect is if
MAX_RT_PRIO != MAX_USER_RT_PRIO, then all priorities are skewed by
(MAX_RT_PRIO - MAX_USER_RT_PRIO).

Ingo, this looks trivial to me... but I swear it _used_ to work and this
function has always been like this. Comments?

Patch is against 2.5.62.

Robert Love

kernel/sched.c | 2 +-
1 files changed, 1 insertion(+), 1 deletion(-)

diff -urN linux-2.5.62/kernel/sched.c linux/kernel/sched.c
--- linux-2.5.62/kernel/sched.c 2003-02-20 18:30:08.232619488 -0500
+++ linux/kernel/sched.c 2003-02-20 18:30:15.585501680 -0500
@@ -1552,7 +1552,7 @@
*/
int task_prio(task_t *p)
{
- return p->prio - MAX_USER_RT_PRIO;
+ return p->prio - MAX_RT_PRIO;
}

/**

-
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