Re: [PATCH] net/ipv4/*, net/core/neighbour.c jiffies cleanup

Krishna Kumar (kumarkr@us.ibm.com)
Thu, 8 Nov 2001 09:47:17 -0800


Hi Linus,

Thanks for your clarification, it does make sense. I did only
the jiffies overflowing case, and missed the case where it
does not overflow.

Thanks,

- KK
-----------------------------------------------------------------------------

Ok.

Let's give an example. HZ is 100, and we started just before jiffies
wrapped, and we want to check that we're within one second.

So "start" equals 0xfffffff0, and "jiffies" equals 0xfffffff5.

The first if-statement will say

if (0xfffffff5 <= 0xfffffff0+100)

which is the same as

if (0xfffffff5 <= 0x54)

which is

if (0)

in short, the first statement will say that jiffies is _not_ within 100
ticks of "start", which is obviously wrong. Jiffies _is_ within 100 ticks,
it is in fact just 5 ticks after "start".

The second statement will say

if (0xfffffff5 - 0xfffffff0 <= 100)

which is

if (5 <= 100)

which is

if (1)

which is _correct_. We _are_ within 100 ticks.

See?

Ok, that was wrap-around one way: the "+HZ" wrapped. Let's see the other
case, which is that "jiffies" has wrapped: start is still 0xfffffff0, but
jiffies has wrapped around and is 0x00000001.

The first if-statement will say

if (0x00000001 <= 0xfffffff0+100)

which is

if (0x00000001 <= 0x54)

which is

if (1)

which is correct. The second one will say

if (0x00000001 - 0xfffffff0 <= 100)

which is

if (11 <= 100)

which is

if (1)

which is correct.

In short, the _correct_ one ALWAYS gets the right answer. Even when the
subtraction overflows.

While the first (and incorrect one) gets the wrong answer when the
addition overflows.

Do you see the difference now?

Linus

-
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