sure! this is the "lots of files" program.
#include <stdio.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
#define BSZ 2000
unsigned char buf[BSZ+256];
main ()
{
    int fd,i,j;
    unsigned int ctr=0;
    unsigned char r=0;
    char f1[32],f2[32],f3[32],f4[32];
    
    while (1)
    {
        sprintf (f1,"fxa_%06d",ctr++);  sprintf (f2,"fxa_%06d",ctr++);
        sprintf (f3,"fxa_%06d",ctr++);  sprintf (f4,"fxa_%06d",ctr++);
        fd = open (f1,O_CREAT | O_RDWR);
        memset (buf,r++,BSZ+256);  write (fd,buf,BSZ+r);    close (fd);
        
        fd = open (f2,O_CREAT | O_RDWR);
        memset (buf,r++,BSZ+256);   write (fd,buf,BSZ+r);    close (fd);
        
        fd = open (f3,O_CREAT | O_RDWR);
        memset (buf,r++,BSZ+256);   write (fd,buf,BSZ+r);     close (fd);
        
        fd = open (f4,O_CREAT | O_RDWR);
        memset (buf,r++,BSZ+256);  write (fd,buf,BSZ+r);      close (fd);
        
        unlink (f1);   unlink (f2);    unlink (f3);   unlink (f4);
        if (!r)
          fprintf (stdout,".");fflush (stdout);
    }
}
and this is the "gimme 300MB even though free sez I hardly have
anything" program:
#define BS (30*1024*1024)
main()
{
    char *x;
    x = malloc (BS);
    if (!x)
        printf ("heh - x is NULL\n");
    else
    {
        printf ("allocd\n");
        memset (x,0x31,BS);
        printf ("set\n");
        free (x);
        printf ("freed\n");
    }
}
> On your machine it'll be "all of swap plus all of physical memory
> minus whatever malloc'ed memory you're using now minus 8-12 megabytes".
> There isn't much memory which cannot be reclaimed unless you have a
> huge machine or you're doing odd things.
this is useful advice, thanks. Basically what the new procps does?
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